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01/14/2025 3:49 AM
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SELECT 'Criterion 1' AS criteria, firstname, lastname, manager, siteid, COUNT(*) AS record_count FROM users GROUP BY firstname, lastname, manager, siteid HAVING COUNT(*) > 1 UNION ALL SELECT 'Criterion 2' AS criteria, firstname, lastname, NULL AS manager, siteid, COUNT(*) AS record_count FROM users GROUP BY firstname, lastname, siteid HAVING COUNT(*) > 1 UNION ALL SELECT 'Criterion 3' AS criteria, lastname, firstname, NULL AS manager, siteid, COUNT(*) AS record_count FROM users GROUP BY lastname, firstname, siteid HAVING COUNT(*) > 1 UNION ALL SELECT 'Criterion 4' AS criteria, NULL AS firstname, NULL AS lastname, NULL AS manager, siteid, COUNT(*) AS record_count FROM users GROUP BY REPLACE(firstname || lastname || siteid, ' ', '') HAVING COUNT(*) > 1;
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