238. Product of Array Except Self
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2 years ago
820 B
22
Indexable
class Solution {
public int[] productExceptSelf(int[] nums) {
int lengthOfArray = nums.length;
int[] answer = new int[lengthOfArray];
int j = 0;
for(int k = 0;k < lengthOfArray;k++){
answer[k] = 1;
}
for(int i = 0;i <= lengthOfArray + 1; i++){
if(j == i){
continue;
}
else if(j != i && i < lengthOfArray && j < lengthOfArray){
answer[j] *= nums[i];
continue;
}
else if(i == lengthOfArray){
continue;
}
else if(i == (lengthOfArray + 1)){
j++;
i = -1;
continue;
}
}
return answer;
}
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