238. Product of Array Except Self
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2 years ago
820 B
18
Indexable
class Solution { public int[] productExceptSelf(int[] nums) { int lengthOfArray = nums.length; int[] answer = new int[lengthOfArray]; int j = 0; for(int k = 0;k < lengthOfArray;k++){ answer[k] = 1; } for(int i = 0;i <= lengthOfArray + 1; i++){ if(j == i){ continue; } else if(j != i && i < lengthOfArray && j < lengthOfArray){ answer[j] *= nums[i]; continue; } else if(i == lengthOfArray){ continue; } else if(i == (lengthOfArray + 1)){ j++; i = -1; continue; } } return answer; } }
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