https://kompege.ru/variant?kim=25026733
user_8840555
python
2 years ago
236 B
11
Indexable
def f(n, m): return n % m == 0 b = list(range(80, 101)) for a in range(1, 10000): for x in range(1, 10000): if (f(x, 17) <= ((not (x in b)) or (a < x + 30))) == 0: break else: print(a)
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