https://kompege.ru/variant?kim=25026733
user_8840555
python
3 years ago
236 B
18
Indexable
def f(n, m):
return n % m == 0
b = list(range(80, 101))
for a in range(1, 10000):
for x in range(1, 10000):
if (f(x, 17) <= ((not (x in b)) or (a < x + 30))) == 0:
break
else:
print(a)Editor is loading...