https://kompege.ru/variant?kim=25026733

 avatar
user_8840555
python
2 years ago
236 B
11
Indexable
def f(n, m):
    return n % m == 0


b = list(range(80, 101))
for a in range(1, 10000):
    for x in range(1, 10000):
        if (f(x, 17) <= ((not (x in b)) or (a < x + 30))) == 0:
            break
    else:
        print(a)
Editor is loading...