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#include <ios>
#include <iostream>
#include <string>
#include <vector>

inline bool leq(int a1, int a2, int b1, int b2) // lexicographic order
{
  return (a1 < b1 || (a1 == b1 && a2 <= b2));
} // for pairs
inline bool leq(int a1, int a2, int a3, int b1, int b2, int b3) {
  return (a1 < b1 || (a1 == b1 && leq(a2, a3, b2, b3)));
} // and triples
// stably sort a[0..n-1] to b[0..n-1] with keys in 0..K from r
static void radixPass(int *a, int *b, int *r, int n,
                      int K) { // count occurrences
  int *c = new int[K + 1];     // counter array
  for (int i = 0; i <= K; i++)
    c[i] = 0; // reset counters
  for (int i = 0; i < n; i++)
    c[r[a[i]]]++;                       // count occurrences
  for (int i = 0, sum = 0; i <= K; i++) // exclusive prefix sums
  {
    int t = c[i];
    c[i] = sum;
    sum += t;
  }
  for (int i = 0; i < n; i++)
    b[c[r[a[i]]]++] = a[i]; // sort
  delete[] c;
}
// find the suffix array SA of s[0..n-1] in {1..K}ˆn
// require s[n]=s[n+1]=s[n+2]=0, n>=2
void suffixArray(int *s, int *SA, int n, int K) {
  int n0 = (n + 2) / 3, n1 = (n + 1) / 3, n2 = n / 3, n02 = n0 + n2;
  int *s12 = new int[n02 + 3];
  s12[n02] = s12[n02 + 1] = s12[n02 + 2] = 0;
  int *SA12 = new int[n02 + 3];
  SA12[n02] = SA12[n02 + 1] = SA12[n02 + 2] = 0;
  int *s0 = new int[n0];
  int *SA0 = new int[n0];
  // generate positions of mod 1 and mod 2 suffixes
  // the "+(n0-n1)" adds a dummy mod 1 suffix if n%3 == 1
  for (int i = 0, j = 0; i < n + (n0 - n1); i++)
    if (i % 3 != 0)
      s12[j++] = i;
  // lsb radix sort the mod 1 and mod 2 triples
  radixPass(s12, SA12, s + 2, n02, K);
  radixPass(SA12, s12, s + 1, n02, K);
  radixPass(s12, SA12, s, n02, K);
  // find lexicographic names of triples
  int name = 0, c0 = -1, c1 = -1, c2 = -1;
  for (int i = 0; i < n02; i++) {
    if (s[SA12[i]] != c0 || s[SA12[i] + 1] != c1 || s[SA12[i] + 2] != c2) {
      name++;
      c0 = s[SA12[i]];
      c1 = s[SA12[i] + 1];
      c2 = s[SA12[i] + 2];
    }
    if (SA12[i] % 3 == 1) {
      s12[SA12[i] / 3] = name;
    } // left half
    else {
      s12[SA12[i] / 3 + n0] = name;
    } // right half
  }
  // recurse if names are not yet unique
  if (name < n02) {
    suffixArray(s12, SA12, n02, name);
    // store unique names in s12 using the suffix array
    for (int i = 0; i < n02; i++)
      s12[SA12[i]] = i + 1;
  } else // generate the suffix array of s12 directly
    for (int i = 0; i < n02; i++)
      SA12[s12[i] - 1] = i;
  // stably sort the mod 0 suffixes from SA12 by their first character
  for (int i = 0, j = 0; i < n02; i++)
    if (SA12[i] < n0)
      s0[j++] = 3 * SA12[i];
  radixPass(s0, SA0, s, n0, K);
  // merge sorted SA0 suffixes and sorted SA12 suffixes
  for (int p = 0, t = n0 - n1, k = 0; k < n; k++) {
#define GetI() (SA12[t] < n0 ? SA12[t] * 3 + 1 : (SA12[t] - n0) * 3 + 2)
    int i = GetI(); // pos of current offset 12 suffix
    int j = SA0[p]; // pos of current offset 0 suffix
    if (SA12[t] < n0
            ? // different compares for mod 1 and mod 2 suffixes
            leq(s[i], s12[SA12[t] + n0], s[j], s12[j / 3])
            : leq(s[i], s[i + 1], s12[SA12[t] - n0 + 1], s[j], s[j + 1],
                  s12[j / 3 + n0])) { // suffix from SA12 is smaller
      SA[k] = i;
      t++;
      if (t == n02) // done --- only SA0 suffixes left
        for (k++; p < n0; p++, k++)
          SA[k] = SA0[p];
    } else { // suffix from SA0 is smaller
      SA[k] = j;
      p++;
      if (p == n0) // done --- only SA12 suffixes left
        for (k++; t < n02; t++, k++)
          SA[k] = GetI();
    }
  }
  delete[] s12;
  delete[] SA12;
  delete[] SA0;
  delete[] s0;
}

int main() {
      std::ios::sync_with_stdio(false);
  std::cin.tie(0);

  std::string str;
  str.reserve(100001);
  std::getline(std::cin, str);

//std::string str = "99 bottles of beer.";

	std::vector<int> data;
	data.reserve(str.size());

	for (char ch : str) {
		data.emplace_back(ch - 32);
	}

    std::vector<int> res(data.size());
    suffixArray(data.data(), res.data(), str.size(), 127-31);

	for (int i = 0; i < res.size(); ++i) {
		std::cout << (res[i] + 1) << " ";
	}
	std::cout << "\n";

    return 0;
}
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