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c_cpp
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nano multi-add.c #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { if (argc < 2) { fprintf(stderr, "Usage: %s <num1> <num2> ... <numN>\n", argv[0]); return 1; } int sum = 0; for (int i = 1; i < argc; i++) { sum += atoi(argv[i]); } printf("Total sum is: %d\n", sum); return 0; }
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