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c_cpp
a month ago
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nano multi-add.c
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    if (argc < 2) {
        fprintf(stderr, "Usage: %s <num1> <num2> ... <numN>\n", argv[0]);
        return 1;
    }

    int sum = 0;
    for (int i = 1; i < argc; i++) {
        sum += atoi(argv[i]);
    }

    printf("Total sum is: %d\n", sum);
    return 0;
}
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