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c_cpp
7 months ago
373 B
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nano multi-add.c
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]) {
if (argc < 2) {
fprintf(stderr, "Usage: %s <num1> <num2> ... <numN>\n", argv[0]);
return 1;
}
int sum = 0;
for (int i = 1; i < argc; i++) {
sum += atoi(argv[i]);
}
printf("Total sum is: %d\n", sum);
return 0;
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