Untitled

unknown

python

a year ago

209 B

Indexable

Never

counter = 0


for n in range(1000, 10000):
    n = str(n)

    if int(n[0]) % 2 == 0:
        r = int(n[0]) + int(n[2]) + abs(int(n[1]) - int(n[3]))
        if r > 20:
            counter += 1

print(counter)