Untitled
unknown
python
2 years ago
256 B
8
Indexable
def F(n): if n < 10: return n elif n % 2 == 0: return F(n % 10) + F(n // 10) else: return F(10**n) + F(n % 10) - 2 counter = 0 for i in range(10*11): if F(i) == 0: counter += 1 print(counter)
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