Untitled
Anonymous
python
08/10/2023 8:20 AM
344 B
28
Indexable
def F(n):
if n < 10:
return n
elif n % 2 == 0:
return F(n % 10) + F(n // 10)
else:
return F(10**n) + F(n % 10) - 2
counter = 0
for i in range(10*11):
if F(i) == 0:
counter += 1
print(counter)Editor is loading...