# 15(13) РТ

user_8840555

python

6 months ago

189 B

Indexable

Never

for a in range(1, 1000):
    for x in range(1, 10000):
        if ((x & 23 == 0)<= ((x & 13 != 0)<= (x & a != 0))) == False:
            break
    else:
        print(a)
# 15(13) РТ