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java
a year ago
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18
Indexable
import java.util.*;
public class Solution {
public static int get_ans(int N, List<Integer> P, List<Integer> A) {
int maxGoodPathLength = 0;
// Check each subarray for the condition
for (int start = 0; start < N; start++) {
int currentXor = 0;
for (int end = start; end < N; end++) {
currentXor ^= A.get(end);
boolean isGoodPath = true;
// Check if all elements in the subarray satisfy the condition
for (int j = start; j <= end; j++) {
if (!(currentXor < A.get(j))) {
isGoodPath = false;
break;
}
}
if (isGoodPath) {
maxGoodPathLength = Math.max(maxGoodPathLength, end - start + 1);
}
}
}
return maxGoodPathLength;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int N = Integer.parseInt(scan.nextLine().trim());
List<Integer> P = new ArrayList<>(N);
for (int j = 0; j < N; j++) {
P.add(Integer.parseInt(scan.nextLine().trim()));
}
List<Integer> A = new ArrayList<>(N);
for (int j = 0; j < N; j++) {
A.add(Integer.parseInt(scan.nextLine().trim()));
}
int result = get_ans(N, P, A);
System.out.println(result);
}
}
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