Untitled

public class Solution {
    public int countBinarySubstrings(String s) {
        int count = 0;
        int prevGroupLength = 0;
        int currentGroupLength = 1;

        for (int i = 1; i < s.length(); i++) {
            if (s.charAt(i) == s.charAt(i - 1)) {
                currentGroupLength++;
            } else {
                // Add the minimum of the previous and current group lengths
                count += Math.min(prevGroupLength, currentGroupLength);
                // Update previous group length and reset current group length
                prevGroupLength = currentGroupLength;
                currentGroupLength = 1;
            }
        }
        // Add the last pair of groups
        count += Math.min(prevGroupLength, currentGroupLength);

        return count;
    }
}