計算1 + 1/2 + 1/3 +...+ 1/N

#include <stdio.h> // printf
int main()
{
	int n;
	scanf_s("%d", &n);
	float sum = 0;
	for (float i = 1; i <= n; i++) {
		sum += (1 / i);
	}
	printf("%3.2f", sum);
}