Untitled
Anonymous
python
05/29/2024 8:03 PM
176 B
10
Indexable
def has22(nums):
for i in range(len(nums) - 1):
if nums[i] == 2 and nums[i + 1] == 2:
return True
return FalseEditor is loading...
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def has22(nums):
for i in range(len(nums) - 1):
if nums[i] == 2 and nums[i + 1] == 2:
return True
return False