replacement
unknown
plain_text
3 years ago
368 B
9
Indexable
def list_replacement(lst,k,new_list):
answer=[]
new=[]
for i in range (len(lst)):
if lst[i]>k:
lst[i]=new_list
new+=lst[i]
return new
temp=[]
for j in new:
for z in j:
temp.append(z)
return temp
return answer
print(list_replacement([6,65,10,4,20],15,[1,2,3]))Editor is loading...