Untitled
unknown
plain_text
9 months ago
987 B
4
Indexable
Step 1. Protonation of Acetic Acid
H+
│
▼
CH₃–C(=O)–OH → CH₃–C(=O⁺H)–OH
(Acetic Acid) (Activated)
Step 2. Nucleophilic Attack by Methanol
CH₃–OH
│
▼
CH₃–C(=O⁺H)–OH + CH₃–OH
│
▼
Tetrahedral Intermediate:
CH₃–C(OH)(OCH₃)–OH
(4-coordinate carbon)
Step 3. Proton Transfer (to convert –OH into a better leaving group)
CH₃–C(OH)(OCH₃)–OH → CH₃–C(OH)(OCH₃)–OH₂⁺
Step 4. Elimination of Water
CH₃–C(OH)(OCH₃)–OH₂⁺
│
▼ (Loss of H₂O)
→ CH₃–C(O⁺H)(OCH₃) + H₂O
(Protonated Ester)
Step 5. Deprotonation to Form the Final Ester
CH₃–C(O⁺H)(OCH₃) → CH₃–C(O)–OCH₃ + H⁺
(Methyl Acetate)Editor is loading...
Leave a Comment