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c_cpp
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#include <bits/stdc++.h>
////////////////////// APPROACH - 2 (BFS)
bool topoSortCycleDetect(int V, vector<int> adj[]) {
queue<int> q;
int indegree[V+1] = {0};
for (int i = 1; i <= V; i++) {
for (int j = 0; j < adj[i].size(); j++) {
indegree[adj[i][j]]++;
}
}
// insert all 0 indegree nodes in queue
for (int i = 1; i <= V; i++)
if (indegree[i] == 0)
q.push(i);
int proccessedNodesCnt = 0;
while (!q.empty()) {
// Nodes in queue have no dependency on any other node (i.e. indegree = 0)
// so process them
int node = q.front();
q.pop();
proccessedNodesCnt++;
for (int i = 0; i < adj[node].size(); i++) {
// Reduce indegree count by 1 of all the nodes which are dependent on processed node.
int connectedNode = adj[node][i];
indegree[connectedNode]--;
// If after reducing indegree count, we got indegree = 0 node. Push it in queue.
if (indegree[connectedNode] == 0)
q.push(connectedNode);
}
}
return proccessedNodesCnt != V;
}
int detectCycleInDirectedGraph(int n, vector < pair < int, int >> & edges) {
vector<int> adjList[n+1];
for (auto edge : edges) {
adjList[edge.first].push_back(edge.second);
}
return topoSortCycleDetect(n, adjList);
}
////////////////////// APPROACH - 1 (DFS)
bool detectCycle(int node, vector<int> adjList[], int visited[]) {
// if node is DfsVisited, cycle exists.
// Note if visited[node] == 1, then cycle doesn’t exist bcz the node is not in current
// dfs call hierarchy.
if (visited[node] == 2)
return true;
// made node DfsVisited, i.e. node is in current dfs call hierarchy
visited[node] = 2;
for (int j = 0; j < adjList[node].size(); j++) {
if (detectCycle(adjList[node][j], adjList, visited))
return true;
}
// make node visited, i.e. it has been visited while traversing, but now its not in
// current dfs call hierarchy.
visited[node] = 1;
return false;
}
int detectCycleInDirectedGraphApproach1(int n, vector < pair < int, int >> & edges) {
vector<int> adjList[n+1];
for (auto edge : edges) {
adjList[edge.first].push_back(edge.second);
}
// 0 -> unvisited, 1 -> visited, 2 -> DfsVisited
// visited -> node has been visited but its not in current dfs call hierarchy.
// DfsVisited -> node has been visited and is in current dfs call hierarchy.
int visited[n+1] = {0};
for (int i = 1; i <= n; i++) {
if (visited[i] == 0) // check for cycle from unvisited nodes
if (detectCycle(i, adjList, visited))
return true;
}
return false;
}
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