dz 15(1)
user_8840555
python
2 years ago
204 B
6
Indexable
def f(n,m):
return n % m == 0
for a in range(1,1000):
for x in range(1,1000):
if ((f(x,30) and (not(f(x,40)))) <= (not(f(x,a)))) == 0:
break
else:
print(a)
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