dz 15(1)
user_8840555
python
2 years ago
204 B
3
Indexable
def f(n,m): return n % m == 0 for a in range(1,1000): for x in range(1,1000): if ((f(x,30) and (not(f(x,40)))) <= (not(f(x,a)))) == 0: break else: print(a)
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def f(n,m): return n % m == 0 for a in range(1,1000): for x in range(1,1000): if ((f(x,30) and (not(f(x,40)))) <= (not(f(x,a)))) == 0: break else: print(a)