dz 15(1)

user_8840555 avatar
user_8840555
python
06/15/2023 3:07 PM
272 B
12
Indexable
def f(n,m):
    return n % m == 0
for a in range(1,1000):
    for x in range(1,1000):
        if ((f(x,30) and (not(f(x,40)))) <= (not(f(x,a)))) == 0:
            break
    else:
        print(a)
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