Untitled
ICS2601 secret lang natin toh conversionunknown
java
3 years ago
4.9 kB
6
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import java.util.*; public class ics2601secret{ static Scanner A = new Scanner(System.in); public static void main(String[]args) { String x; do {System.out.println("Please enter the base of the number:"); int base=A.nextInt(),number; //else if statments used since there is more than one condition and swtich can't be used since there is more than 11 different cases if (base<10&&base>1) { System.out.println("Please enter the number:"); number=A.nextInt(); //used to collect the number to be converted to base 10 switch(base) //basic switch statement just changed the method that will be used to print everything { case 2: System.out.println("The number "+number+" in the base "+base+" is "+base2(number)+" in the base 10"); break; case 3: System.out.println("The number "+number+" in the base "+base+" is "+base3(number)+" in the base 10"); break; case 4: System.out.println("The number "+number+" in the base "+base+" is "+base4(number)+" in the base 10"); break; case 5: System.out.println("The number "+number+" in the base "+base+" is "+base5(number)+" in the base 10"); break; case 6: System.out.println("The number "+number+" in the base "+base+" is "+base6(number)+" in the base 10"); break; case 7: System.out.println("The number "+number+" in the base "+base+" is "+base7(number)+" in the base 10"); break; case 8: System.out.println("The number "+number+" in the base "+base+" is "+base8(number)+" in the base 10"); break; case 9: System.out.println("The number "+number+" in the base "+base+" is "+base9(number)+" in the base 10"); break; } } else if (base>10) { System.out.println("Base cannot be greater than 10!"); } else if (base==1) { System.out.println("Base cannot be equal to 1!"); } System.out.println("Do you wish to continue? (y/n)"); x = A.next().toUpperCase(); } while(x.equals("Y")); } //formula is all the same just change the number multiplied to 1 by the base static int base2(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*2; } return decimal; //returns number converted from base n to base 10 } static int base3(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall+base; base = base*3; } return decimal; } static int base4(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*4; } return decimal; } static int base5(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*5; } return decimal; } static int base6(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*6; } return decimal; } static int base7(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*7; } return decimal; } static int base8(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*8; } return decimal; } static int base9(int a) { int n = a,decimal=0,x,base=1,finall; for(x=n;x>0;) { finall = x%10; x = x/10; decimal += finall*base; base = base*9; } return decimal; } }
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