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The first fit memory allocation strategy is a technique used in operating systems to allocate memory to processes. It involves searching for the first available memory partition or hole that is large enough to accommodate the process. The operating system starts searching from the beginning of the memory and assigns the process to the first suitable free partition it encounters. Here's how the first fit algorithm works: 1. The operating system maintains a list of memory partitions, each with its size and status (free or occupied). 2. When a process needs to be allocated memory, the operating system searches the list of partitions from the beginning. 3. It looks for the first partition that is both free and large enough to accommodate the process. 4. Once a suitable partition is found, the process is allocated to that partition, and the status of the partition is updated to "occupied." 5. If no suitable partition is found, the process may not be allocated memory, or it may be placed in a waiting queue until memory becomes available. The first fit strategy has the advantage of being the fastest search algorithm because it only needs to search the first block that is sufficient to assign a process. However, it may suffer from the problem of not allowing processes to take space even if it was possible to allocate memory. This can lead to suboptimal memory utilization and fragmentation. Compiler: CodeBlocks Language: C Source Code #include <stdio.h> int main() { int bsize[10], psize[10], bno, pno, flags[10], allocation[10], i, j; for(i = 0; i < 10; i++) { flags[i] = 0; allocation[i] = -1; } printf("Enter the number of memory blocks: "); scanf("%d", &bno); printf("Enter the size of each memory block: \n"); for(i = 0; i < bno; i++) { scanf("%d", &bsize[i]); } printf("Enter the number of processes: "); scanf("%d", &pno); printf("Enter the size of each process: \n"); for(i = 0; i < pno; i++) { scanf("%d", &psize[i]); } for(i = 0; i < pno; i++) { for(j = 0; j < bno; j++) { if(flags[j] == 0 && bsize[j] >= psize[i]) { allocation[i] = j; flags[j] = 1; break; } } } printf("\nProcess No.\tProcess Size\tBlock no.\n"); for(i = 0; i < pno; i++) { printf("%d\t\t%d\t\t", i+1, psize[i]); if(allocation[i] != -1) { printf("%d\n", allocation[i]+1); } else { printf("Not Allocated\n"); } } return 0; }
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