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/************************************************************ JAVA ************************************************/ //Approach-(simple remainder maths) //T.C : O(n) //S.C : O(k) class Solution { public boolean canArrange(int[] arr, int k) { int[] mp = new int[k]; // Array to store remainders frequency // Calculate the remainder frequencies for (int num : arr) { int rem = (num % k + k) % k; // Handle negative remainders mp[rem]++; } // Check if the frequency of numbers with 0 remainder is even if (mp[0] % 2 != 0) { return false; } // Check if each remainder has a complement remainder with matching frequency for (int rem = 1; rem <= k / 2; rem++) { int counterHalf = k - rem; if (mp[counterHalf] != mp[rem]) { return false; } } return true; } }
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