Untitled
unknown
python
a year ago
608 B
8
Indexable
class Solution: def canPartition(self, nums: List[int]) -> bool: # if valid partition, sum of one subset = sum(nums) / 2 # find a valid partition by backtracking valid combinations if sum(nums) % 2 == 1: return False target = sum(nums) / 2 def backtrack(currSum, start): if currSum == target: return True if currSum > target or start >= len(nums): return False return backtrack(currSum + nums[start], start+1) or backtrack(currSum, start+1) return backtrack(0, 0)
Editor is loading...
Leave a Comment