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5 months ago
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Excellent question. To solve this space-efficient version, we can modify our
approach as follows:
Replace TreeMap with a fixed-size array or circular buffer
Use binary search for efficient retrieval
Implement a custom eviction policy
Here's a possible implementation in Java:
class TimeMap {
private static final int N = 5; // Number of recent values to keep per key
private Map<String, TimestampedValue[]> map;
private static class TimestampedValue {
int timestamp;
String value;
TimestampedValue(int timestamp, String value) {
this.timestamp = timestamp;
this.value = value;
}
}
public TimeMap() {
map = new HashMap<>();
}
public void set(String key, String value, int timestamp) {
TimestampedValue[] values = map.computeIfAbsent(key, k -> new
        TimestampedValue[N]);
int index = findInsertionIndex(values, timestamp);
if (index < N) {
// Shift elements if necessary
System.arraycopy(values, index, values, index + 1, Math.min(N - index -
            1, values.length - index - 1));
values[index] = new TimestampedValue(timestamp, value);
}
}
public String get(String key, int timestamp) {
TimestampedValue[] values = map.get(key);
if (values == null) return "";
int index = findFloorIndex(values, timestamp);
return index >= 0 ? values[index].value : "";
}
private int findInsertionIndex(TimestampedValue[] values, int timestamp) {
int left = 0, right = N - 1;
 
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