Untitled
unknown
plain_text
2 years ago
1.3 kB
7
Indexable
SELECT
c.candidatename,
t.skill,
t.experience AS highest_experience
FROM
candidates c
JOIN (
SELECT
SUBSTRING_INDEX(skills, ',', 1) AS skill,
CAST(SUBSTRING_INDEX(experience_years, ',', 1) AS UNSIGNED) AS experience
FROM
candidates
UNION ALL
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(skills, ',', numbers.n), ',', -1) AS skill,
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(experience_years, ',', numbers.n), ',', -1) AS UNSIGNED) AS experience
FROM
candidates
JOIN (
SELECT
(a.N + b.N * 10 + 1) AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
) AS numbers ON CHAR_LENGTH(skills) - CHAR_LENGTH(REPLACE(skills, ',', '')) >= numbers.n - 1
) AS t ON SUBSTRING_INDEX(c.skills, ',', 1) = t.skill
AND CAST(SUBSTRING_INDEX(c.experience_years, ',', 1) AS UNSIGNED) = t.experience
GROUP BY
c.candidatename, t.skill;
Editor is loading...
Leave a Comment