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java
5 months ago
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import java.util.*;
import java.lang.*;
import java.io.*;

class LinearSearch
{
	public static void main (String[] args) throws java.lang.Exception
	{
		int arr[]={1,2,3,4,5,6,7,8,9,10};
		Scanner s=new Scanner(System.in);
		int t=s.nextInt();
		for(int i=0; i<arr.length;i++){
		    if(t==arr[i]){
		        System.out.println(i);
		    }else{
		        System.out.println("Number is not found");
		    }
		}
	}
}
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