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java
5 months ago
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import java.util.*; import java.lang.*; import java.io.*; class LinearSearch { public static void main (String[] args) throws java.lang.Exception { int arr[]={1,2,3,4,5,6,7,8,9,10}; Scanner s=new Scanner(System.in); int t=s.nextInt(); for(int i=0; i<arr.length;i++){ if(t==arr[i]){ System.out.println(i); }else{ System.out.println("Number is not found"); } } } }
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