16

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unknown
plain_text
2 years ago
128 B
5
Indexable
n = [1, 2, 3, 4, 5]
for i in n:
    print(i, i * 1.057, i - 12.22)

print(*((i, i * 1.057, i - 12.22) for i in n), sep='\n')
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