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c_cpp
4 years ago
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#include <bits/stdc++.h>
using namespace std;
int merge(int arr[], int temp[], int left, int mid, int right)
{
int i, j, k;
int inv_count = 0;
i = left;
j = mid;
k = left;
while ((i <= mid - 1) && (j <= right))
{
if (arr[i] <= arr[j])
{
temp[k++] = arr[i++];
}
else
{
temp[k++] = arr[j++];
inv_count = inv_count + (mid - i);
}
}
while (i <= mid - 1)
{
temp[k++] = arr[i++];
}
while (j <= right)
{
temp[k++] = arr[j++];
}
for (i = left; i <= right; i++)
{
arr[i] = temp[i];
}
return inv_count;
}
int mergeSort(int arr[], int temp[], int left, int right)
{
int mid;
int cnt1 =0, cnt2 = 0, cnt3 =0;
if (right > left)
{
mid = (right + left) / 2;
cnt1 += mergeSort(arr, temp, left, mid);
cnt2 += mergeSort(arr, temp, mid + 1, right);
cnt3 += merge(arr, temp, left, mid + 1, right);
}
return (cnt1 + cnt2 + cnt3);
}
int inversionCount(int arr[], int array_size)
{
int temp[array_size];
return mergeSort(arr, temp, 0, array_size-1);
}
int main()
{
int arr[] = { 2,4,1,3,5};
int arr_size = sizeof(arr) / sizeof(arr[0]);
int inversionCnt = inversionCount(arr, arr_size);
cout<<" Number of inversions are: "<<inversionCnt;
return 0;
}
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