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Michael
python
a year ago
1.7 kB
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'''
2024-7-4
計算那張圖
'''

def 新算法(LE,SV,LIC,LICV,LT,PCV,PC):
    
    if (LE and SV):
        # LA1=LA2=LA3=the_burner=True
        return True
    elif SV:
        # SV=True, LE=False
        # LA2 = LA3 = The_burner = True
        LA1=(LIC or LICV)
        return LA1
    elif LE:
        # SV=False LA1=LA2=True
        # The_burner=LA3=result
        LA3=(PC or PCV)
        return LA3
    else:
        if LIC:
            # LE=SV=False
            # LA1=LA2=True LIC=True
            LA3=(PC or PCV)
            # the_burner=LA3
            return LA3
        else:
            if PCV:
                # LE=SV=LIC=False
                # LA2=LA3=the_burner=True
                # LA1=LICV
                return LICV
            else:
                # LE=SV=LIC=PCV=False
                LA1=LICV
                LA2=LT
                LA3=PC
                the_burner=(LA2 and LA3)   
                return (LA1 and the_burner)    



def 老算法(LE,SV,LIC,LICV,LT,PCV,PC):
    LA3=(PCV or SV or PC)
    print('LA3 = {}'.format(LA3))

    LA2=(LE or LIC or LT or SV)
    print('LA2 = {}'.format(LA2))

    LA1=(LE or LIC or LICV)
    print('LA1 = {}'.format(LA1))

    The_burner=(LA2 and LA3)
    print('The_burner = {}'.format(The_burner))

    breakup_of_the_steam=(LA1 and The_burner)
    print('breakup_of_the_steam = {}'.format(breakup_of_the_steam))

    return breakup_of_the_steam 



LE=True
LIC=False
LICV=False
LT=False
SV=False
PCV=False
PC=False


print('新算法')  
print(新算法(LE,SV,LIC,LICV,LT,PCV,PC))  
print('老算法')  
print(老算法(LE,SV,LIC,LICV,LT,PCV,PC))  

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