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python
2 years ago
420 B
2
Indexable
Never

def tasks(n,a,b):

    list_pair = []

    for i in range(1,len(a)):
        list_pair.append([a[i],b[i]])

    count = 0
    for i in range(len(a)-1):
        
        tmp = list_pair[i].copy()
        tmp.reverse()
        
        if(tmp[0]==tmp[1] and list_pair.count(tmp)>1):
            count +=1

        elif(tmp[0]!=tmp[1] and tmp in list_pair):
            count += 1
               
    return int(n-count/2)