# Bondhu

unknown
c_cpp
a month ago
1.8 kB
5
Indexable
Never
```/*
* Write a program in any language to find the sum of rows and columns of a m x n matrix,
* where m and n is taken input from the user. Give the output in the following format
* input
* 4 * 3 matrix
* 1 2 3 4
* 5 6 7 8
* 9 0 1 2
*
* output
* 1 2 3 4   | 10
* 5 6 7 8   | 26
* 9 0 1 2   | 12
* ----------|-----
* 15 8 11 14|
* */

#include <stdio.h>
#include <string.h>

int main() {
// Initializing row and column count;
int row = 0, col = 0;
// Taking row and column input;
scanf("%d %d", &row, &col);
printf("Number of rows and columns: %d %d\n", row, col);
// From example, we saw, there will be an extra row and an extra column;
// That's why decalring an m+1 * n+1 matrix
// this will make calculation easier
int matrix[row+1][col+1];
// Setting all of the entries of matrix to 0, mainly needed for result
memset(matrix, 0, sizeof(matrix));
// Essential variable for loop
int i,j;
// Initial state of our matrix
printf("Matrix initial\n");
for (i=0;i<row + 1;i++) {
for (j=0;j<col + 1;j++) {
printf("%d ", matrix[i][j]);
}
printf("\n");
}
// While we are taking input, we are also adding current number to row result mat[currentRow][column] entry.
// We are also adding current number to column result entry matrix[row][currentColumn]
// If we do this way, then we don't need to do another O(n^2) loop
for (i=0;i<row;i++) {
for (j=0;j<col;j++) {
scanf("%d", &matrix[i][j]);
matrix[i][col] += matrix[i][j];
matrix[row][j] += matrix[i][j];
}
}
printf("Matrix after input\n");
for (i=0;i<row + 1;i++) {
for (j=0;j<col + 1;j++) {
// Skipping last entry
if (i == row && j == col) continue;
printf("%d ", matrix[i][j]);
}
printf("\n");
}
return 0;
}```