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haskell
a year ago
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Indexable
z :: [Int] -> Int
z x = 0

n :: [Int] -> Int
n x = 1 + head x

u :: Int -> Int -> [Int] -> Int
u _ k x = x !! (k-1)

mapFuns :: [[Int] -> Int] -> [Int] -> [Int]
mapFuns fs l = ($ l) <$> fs

s :: ([Int] -> Int) -> [[Int] -> Int] -> [Int] -> Int
s g f x = g  (mapFuns f x)

r :: ([Int] -> Int) -> ([Int] -> Int) -> [Int] -> Int -> Int
r f g x y
  | y == 0 = f x
  | otherwise = g  (x ++ [y - 1, r f g x (y - 1)])

plus :: [Int] -> Int
plus x = r (u 1 1) (s n [u 3 3]) [head x]  (head (tail x))

multiply :: [Int] -> Int
multiply x = r z (s plus [u 3 1, u 3 3]) [head x] (head (tail x))

dec :: [Int] -> Int
dec a = r z(u 3 2) a (head a)

limited_minus :: [Int] -> Int
limited_minus a = r (u 1 1) (s dec [u 3 3]) [head a] (head (tail a))

le :: [Int] -> Int
le x =  r (s n [dec]) (s dec [u 3 3]) [limited_minus x] (limited_minus x)

divide :: [Int] -> Int
divide a = r z (s plus [s le [s multiply [u 4 2, s n [u 4 3]], u 4 1], u 4 4]) a (head a)

modul :: [Int] -> Int
modul a = s limited_minus [u 2 1, s multiply [u 2 2, s divide [u 2 1, u 2 2]]] a


-- func 1 = x / y^k, witk k = max
-- func1 a b
-- max k : b^k a % b^k == 0
-- a / b^k
func1 :: [Int] -> Int
func1 a = r (u 2 1) (s divide [u 4 4, s limited_minus [s plus [s n [z], s multiply [s le [s modul [u 4 4, u 4 2], z], u 4 2]], s le [s modul [u 4 4, u 4 2], z]]]) a  (head a)

-- func2 = log_x(y), if exist k : y = x^k
func2 :: [Int] -> Int
func2 a = r z (s plus [s multiply [s le [s modul [s n [u 4 3], u 4 2], z], s le [s modul [u 4 1, s n [u 4 3]], z]], u 4 4]) a (head a)

plog :: [Int] -> Int
plog a = s func2 [s divide [u 2 1, s func1 [u 2 1, u 2 2]], u 2 2] a

a :: Int
a = plog[96, 2]

main :: IO ()
main = do
  print a
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