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user_8556937499
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4 years ago
987 B
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SELECT c.company_code,c.founder, COUNT(DISTINCT lm.lead_manager_code), COUNT(DISTINCT sm.senior_manager_code), COUNT(DISTINCT m.manager_code), COUNT(DISTINCT e.employee_code) FROM Company c, Lead_Manager lm, Senior_Manager sm, Manager m, Employee e WHERE c.company_code=lm.company_code AND lm.lead_manager_code=sm.lead_manager_code AND sm.senior_manager_code=m.senior_manager_code AND m.manager_code=e.manager_code GROUP BY c.company_code,c.founder ORDER BY c.company_code ASC /* Enter your query here. */ -- SELECT c.company_code, c.founder, -- COUNT(DISTINCT(lm.lead_manager_code)), -- COUNT(DISTINCT(sm.lead_manager_code)), -- COUNT(DISTINCT(m.lead_manager_code)), -- COUNT(DISTINCT(e.lead_manager_code)), tam, tsm, tm, te -- FROM -- Company AS c, -- Lead_Manager AS lm, -- Senior_Manager AS sm, -- Manager AS m, -- Employee AS e -- WHERE c.company_code = lm.company_code = sm.company_code = m.company_code = e.company_code -- ORDER BY company_code ASC
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