Untitled
unknown
plain_text
2 years ago
291 B
6
Indexable
SELECT s.username, COUNT(cs.id) AS total_streams, AVG(cs.viewers) AS avg_viewers FROM streamers s JOIN completed_streams cs ON s.id = cs.streamer_id GROUP BY s.id HAVING COUNT(cs.id) > 5 AND AVG(cs.viewers) > 5000 ORDER BY avg_viewers DESC;
Editor is loading...
Leave a Comment