Reverse Integer Solution
unknown
java
a year ago
395 B
6
Indexable
class Solution { public int reverse(int x) { int reversedInt = 0; while(x!=0){ int digit = x%10; if(reversedInt < Integer.MIN_VALUE/10 || reversedInt > Integer.MAX_VALUE/10){ return 0; } reversedInt = (reversedInt * 10) + digit; x = x/10; } return reversedInt; } }
Editor is loading...
Leave a Comment