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prolog
2 years ago
783 B
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%connections work both ways is_connected(A,B) :- con_test(A,B). is_connected(A,B) :- con_test(B,A). %recursion rule no printing %con_test(A,B) :- con(A,B). %con_test(A,B) :- con(A,X), con_test(X,B) %recursion rule with printing con_test(A,B) :- con(A,B), write(A), write(" connected to "), writeln(B). con_test(A,B) :- con(A,X), con_test(X,B), write(A), write(" connected to "), writeln(X). %--------------- % knowledgebase %--------------- % ZERO -> 26+5+18+15 -> 64 con(0,64). con(1,34). con(2,58). con(3,56). con(4,60). con(5,42). con(6,52). con(7,65). con(8,49). con(9,42). % ZERO -> 26+5+18+15 -> 64 -> 10 -> 1 con(0,1). con(1,7). con(2,4). con(3,2). con(4,6). con(5,6). con(6,7). con(7,2). con(8,4). con(9,6).
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