ham kiem tra
unknown
plain_text
2 years ago
278 B
3
Indexable
bool is_ok(){
int sum = 0, num = 0, sign = 1;
for(int i = 0; i < 2*n - 1; i++){
if(i % 2 == 0){
num = num*10 + arr[i];
}
else{
if(arr[i] == 0) {continue;}
sum += num*sign;
num = 0;
sign = arr[i];
}
}
sum += num*sign;
return sum == 0;
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