1/1+1/2+1/3+...+1/N

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user_3763047219
c_cpp
2 years ago
147 B
3
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int main()
{
	int N = 0;
	float sum=0;
	scanf("%d", &N);
	for (float i = 1; i <= N; i++) {
		sum = sum + 1 / i;
	}
	printf("%.2f", sum);
}
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