kaveh
unknown
c_cpp
4 years ago
1.1 kB
10
Indexable
// IN THE NAME OF ALLAH.
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define F first
#define S second
#define pb push_back
const int N = 257;
int dp[N][N][N], a[N];
int32_t main(){
ios::sync_with_stdio(false);
int d, k;
cin >> d >> k;
for(int i = 0; i < d; i++){
int c, e;
cin >> c >> e;
a[c] = e;
}
for(int i = 0; i < N; i++){
for(int j = 1; j <= i + 1; j++){
for(int l = j - 1; l < i; l++)
dp[i][j][l] = dp[i - 1][j][l] + a[i] * (i - l) * (i - l);
if(j == 1){
for(int l = 0; l < i; l++)
dp[i][j][i] += a[l] * (i - l) * (i - l);
}
else{
int cost = 0;
dp[i][j][i] = dp[i - 1][j - 1][i - 1];
for(int l = i - 1; 2 * l >= i; l--){
cost += a[l] * (i - l) * (i - l);
dp[i][j][i] = min(dp[i][j][i], dp[l - 1][j - 1][2 * l - i] + cost);
if(2 * l - 1 >= i)
dp[i][j][i] = min(dp[i][j][i], dp[l - 1][j - 1][2 * l - i - 1] + cost);
}
}
}
}
int ans = dp[N - 1][k][k - 1];
for(int i = k; i < N; i++)
ans = min(ans, dp[N - 1][k][i]);
cout << ans << '\n';
return 0;
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