Задание 5 Номер КИМ: 16
user_8840555
python
2 years ago
384 B
5
Indexable
def f(n):
if n <= 19:
return n * n * n + 22
if n % 3 == 0 and n > 19:
return f(n - 4) + f(n - 8)
if n % 3 != 0 and n > 19:
return f(n - 9) + n + 7
c = 0
for n in range(1, 101):
s = str(f(n))
if s.count('1') == 0 and s.count('3') == 0 and s.count('5') == 0 and s.count('7') == 0 and s.count('9') == 0:
c += 1
print(c)Editor is loading...