Задание 5 Номер КИМ: 16
user_8840555
python
2 years ago
384 B
4
Indexable
def f(n): if n <= 19: return n * n * n + 22 if n % 3 == 0 and n > 19: return f(n - 4) + f(n - 8) if n % 3 != 0 and n > 19: return f(n - 9) + n + 7 c = 0 for n in range(1, 101): s = str(f(n)) if s.count('1') == 0 and s.count('3') == 0 and s.count('5') == 0 and s.count('7') == 0 and s.count('9') == 0: c += 1 print(c)
Editor is loading...