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This is one function-

def purge_logs():
    vm_details = get_vm_details()
    for vm in vm_details:
        vm_id = vm['vm_id']
        vm_ip = vm['vm_ip']
        syslog_file = vm['syslog_file_location']
        retention_period = get_retention_period(vm_id)
        
        print("VM:", vm_id)
        print("VM_IP:", vm_ip)
        bookmark_record=str(vm_ip) + "_bookmark_log"
        print("Bookmark record ",bookmark_record)
        print("Syslog File Location:", syslog_file)
        print("Retention Period:", retention_period)
        current_date = str(datetime.datetime.now()).split(' ')[0]
        print(current_date)
        
        #print("Purging Logs...")
        
        
        try:
            with open(syslog_file,'r') as file:
                for line in file:
                    if str(current_date) in line:
                        #print(line)
                        x = line
                        
        except Exception as e:
            print("File not found :",e)
                    
        

purge_logs()
        


here in try block we need first occurence of that line found and note its line number and all the lines before that line should be deleted/purged . 

Can you help here please as based on current date we are finding the first line of today's date and deleting all earlier records.
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