Q2_m

select
    c.company_code,
    c.founder,
    count(distinct l.lead_manager_code),
    count(distinct s.senior_manager_code),
    count(distinct m.manager_code),
    count(distinct e.employee_code)
from
    company c,
    lead_manager l,
    senior_manager s,
    manager m,
    employee e
where c.company_code = l.company_code
    and l.lead_manager_code = s.lead_manager_code
    and s.senior_manager_code = m.senior_manager_code
    and m.manager_code = e.manager_code
group by c.company_code, c.founder
order by c.company_code asc;