Question 1

user_6227789376 avatar
user_6227789376
mysql
11/19/2021 9:47 AM
360 B
15
Indexable
-- Medium
-- Question 1 (the Paid):

SELECT CONCAT(name,'(',LEFT(occupation, 1),')') 
FROM occupations 
ORDER BY name;

SELECT CONCAT('There are a total of ', COUNT(*), ' ', LOWER(occupation), 's.') 
FROM occupations 
GROUP BY occupation 
ORDER BY COUNT(*), occupation;
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