Count Inversions
Using Merge Sortimport java.util.*; public class tUf { private static int merge(int[] arr, int low, int mid, int high) { ArrayList<Integer> temp = new ArrayList<>(); // temporary array int left = low; // starting index of left half of arr int right = mid + 1; // starting index of right half of arr //Modification 1: cnt variable to count the pairs: int cnt = 0; //storing elements in the temporary array in a sorted manner// while (left <= mid && right <= high) { if (arr[left] <= arr[right]) { temp.add(arr[left]); left++; } else { temp.add(arr[right]); cnt += (mid - left + 1); //Modification 2 right++; } } // if elements on the left half are still left // while (left <= mid) { temp.add(arr[left]); left++; } // if elements on the right half are still left // while (right <= high) { temp.add(arr[right]); right++; } // transfering all elements from temporary to arr // for (int i = low; i <= high; i++) { arr[i] = temp.get(i - low); } return cnt; // Modification 3 } public static int mergeSort(int[] arr, int low, int high) { int cnt = 0; if (low >= high) return cnt; int mid = (low + high) / 2 ; cnt += mergeSort(arr, low, mid); // left half cnt += mergeSort(arr, mid + 1, high); // right half cnt += merge(arr, low, mid, high); // merging sorted halves return cnt; } public static int numberOfInversions(int[] a, int n) { // Count the number of pairs: return mergeSort(a, 0, n - 1); } public static void main(String[] args) { int[] a = {5, 4, 3, 2, 1}; int n = 5; int cnt = numberOfInversions(a, n); System.out.println("The number of inversions are: " + cnt); } }
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