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python
a year ago
741 B
4
Indexable
def solution(stationsA, stationsB, stationsC, origin, destination): o, d = ' ', ' ' for station in stationsA: if origin == station: o = 'A' if destination == station: d = 'A' for station in stationsB: if origin == station: o = 'B' if destination == station: d = 'B' for station in stationsC: if origin == station: o = 'C' if destination == station: d = 'C' if d == ' ' or o == ' ': return "" if o == 'A' and d == 'B': return "AB" if o == 'A' and d == 'C': return "ABC" if o == 'B' and d == 'C': return "BC" return ""
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