# visually

unknown
python
2 years ago
1.9 kB
105
Indexable
Never
```
def calCount(arr):
dp = {}
dp[len(arr)-1] = [True,"a"]
for i in range(len(arr) - 2,-1,-1):
if arr[i] > arr[i+1]:
t = "d"
if dp[i+1][1] == "a" or dp[i+1][1] == "i":
dp[i] = [True and dp[i+1][0], "d"]
else:
dp[i] = [False, "d"]
else:
t = "i"
if dp[i+1][1] == "a" or dp[i+1][1] == "d":
dp[i] = [True and dp[i+1][0], "i"]
else:
dp[i] = [False, "i"]
print(dp)
dp_end = {}
dp_end[0] = [True,"a"]
for i in range(1, len(arr)):
if arr[i] < arr[i-1]:
t = "d"
if dp_end[i-1][1] == "a" or dp_end[i-1][1] == "i":
dp_end[i] = [True and dp_end[i-1][0], "d"]
else:
dp_end[i] = [False, "d"]
else:
t = "i"
if dp_end[i-1][1] == "a" or dp_end[i-1][1] == "d":
dp_end[i] = [True and dp_end[i-1][0], "i"]
else:
dp_end[i] = [False, "i"]

print(dp_end)
if dp[0] == True:
return 0

count = -1

if dp[1][0] == True:
print("true 1")
count = count+1
if dp_end[len(arr)-2][0] == True:
print("true 2")
count = count+1
print("count : ", count)
for i in range(1,len(arr)-1):
print("i : ", i)
t = "n"
if arr[i-1] > arr[i+1]:
t = "d"
elif arr[i-1] < arr[i+1]:
t = "i"
print("t : ", t)
if t != dp[i+1][1] and dp[i+1][0] == True and dp_end[i-1][0] == True :
count = count +1
print("count : ", count)
#     print(count)

if count == 0:
return -1
return count+1
def main():
s = input()
arr = list(map(int,s.split()))
print(arr)
print(calCount(arr))
main()```