Untitled
unknown
plain_text
2 years ago
603 B
3
Indexable
class Solution { public: void nextPermutation(vector<int>& nums) { int n=nums.size(); int ind=-1; for(int i=n-2;i>=0;i--){ if(nums[i]<nums[i+1]){ ind=i; break; } } if(ind==-1) { reverse(nums.begin(),nums.end()); return; } for(int i=n-1;i>=ind;i--){ if(nums[i]>nums[ind]){ swap(nums[i],nums[ind]); break; } } reverse(nums.begin()+ind+1,nums.end()); } };
Editor is loading...
Leave a Comment