# finding sublists

unknown
python
2 years ago
1.6 kB
2
Indexable
Never
```list_nums = [1, 2, 5, 7, 9, 19, 23, 4, 3, 2, 2, 6, 7, 8]

def find_sublists(list_nums):
"""
Return list of sublists and index start and end for each sublist.
Find sublists that start with 1,2,3 but no entry should exceed 10.
Example:
list_nums = [1,2,5,7,9,19,23,4,3,2,2,6,7,8]
Output:
- sub_lists = [[1,2,5,7,9],[3,2,2,6,7,8]]
- sub_lists_index = [(0,4),(8,13)]
"""
sub_lists = []
sub_lists_index = []

new_sub_list = []
new_sub_list_index = []

for i in range(len(list_nums)):
if list_nums[i] == 1 or list_nums[i] == 2 or list_nums[i] == 3:
if len(new_sub_list) == 0:
new_sub_list.append(list_nums[i])
new_sub_list_index.append(i)
else:
new_sub_list.append(list_nums[i])
elif list_nums[i] > 10:
if len(new_sub_list) > 0:
new_sub_list_index.append(i - 1)
sub_lists.append(new_sub_list)
sub_lists_index.append(new_sub_list_index)
new_sub_list = []
new_sub_list_index = []
else:
continue
else:
if len(new_sub_list) > 0:
new_sub_list.append(list_nums[i])
if i == len(list_nums) - 1:
if len(new_sub_list) > 0:
new_sub_list_index.append(i)
sub_lists.append(new_sub_list)
sub_lists_index.append(new_sub_list_index)

return sub_lists, sub_lists_index

ans = find_sublists(list_nums)
print(ans[0])
print(ans[1])
```