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#include<iostream>
using namespace std;
int t, m, n, a[51][51], p, r, c, cnt, ploang;
int front , rear,q1[51 * 51] , q2[51 * 51], visited[51][51];
int dx[] = {-1,0,1,0};
int dy[] = {0, 1,0,-1};
//bool ket_noi[8][4] =
//{
// {0, 0, 0, 0},
// {1, 1, 1, 1},
// {1, 0, 1, 0},
// {0, 1, 0, 1},
// {1, 1, 0, 0},
// {0, 1, 1, 0},
// {0, 0, 1, 1},
// {1, 0, 0, 1}
//};
void BFS(int x, int y)
{
q1[++rear] = x;
q2[rear] = y;
int b = 0, c = 0;
while (front != rear)
{
int u = q1[++front];
int v = q2[front];
b = a[u][v];
if(visited[u][v] == p)
break;
for (int k = 0; k < 4; k++)
{
/*if(!ket_noi[a[u][v]][k])
continue;*/
int tx = u + dx[k];
int ty = v + dy[k];
c = a[tx][ty];
if( tx < 0 || tx == n || ty < 0 || ty == m || !a[tx][ty] || visited[tx][ty] )
continue;
// int check = noi_ong(u, v, tx , ty);
if(k == 0 && b == 1 || b == 2 || b == 4 || b == 7 && c ==1 || c == 2 || c == 5 || c == 6)
{
visited[tx][ty] = visited[u][v] + 1;
q1[++rear] = tx;
q2[rear] = ty;
cnt++;
}
else if(k == 1 && b == 1 ||| b == 3|| b == 4 || b == 5 && c == 1 || c == 3 || c == 6 || c == 7)
{
visited[tx][ty] = visited[u][v] + 1;
q1[++rear] = tx;
q2[rear] = ty;
cnt++;
}
else if( k == 2 && b == b == 1 || b == 2 || b == 5 || b == 6 && c == 1 || c == 2 || c == 4 || c == 7)
{
visited[tx][ty] = visited[u][v] + 1;
q1[++rear] = tx;
q2[rear] = ty;
cnt++;
}
else if( k == 3 && b == 1 || b == 3 || b == 6 || b == 7 && c == 1 || c == 3 || c == 6 || c == 7)
{
visited[tx][ty] = visited[u][v] + 1;
q1[++rear] = tx;
q2[rear] = ty;
cnt++;
}
else
continue;
}
}
}
int main()
{
//freopen("t.txt", "r", stdin);
cin >> t;
for (int tc = 1; tc <= t; tc++)
{
cin >> m >> n >> r >> c >> p;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
cin >> a[i][j];
visited[i][j] = 0;
}
}
cnt = 1;
visited[r][c] = 1;
front = -1;
rear = -1 ;
BFS(r, c);
cout <<"Case #" << tc << endl<< cnt << endl;
}
return 0;
}
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