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python
4 years ago
772 B
4
Indexable
def slovag(n): if n == 0: yield '' elif n == 1: yield '0' yield '1' else: for el in slovag(n-1): # if el[-1] != '0': if '000' not in el + '0': yield el+'0' yield el+'1' def convert_from_binary_to_decimal(binary_num): cislo = 0 index = 0 for i in reversed(range(len(binary_num))): cislo += (2 ** index) * (int(binary_num[i]) % 2) index += 1 return cislo def sucetPrvychk(k, n): res = 0 num_of_added = 0 for slovo in slovag(n): res += int(slovo) num_of_added += 1 if num_of_added == k: break return res % (10**9 + 7)
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