Untitled
unknown
plain_text
2 years ago
1.4 kB
6
Indexable
clear; clc; // zad 1 r = 4 n_max = 50 a = 0.5 b = 2 h = 0.001 // zad 2 function y=f(x); y = (x^2 - 3)*sin(x) endfunction // zad 3 function y=fp(x,h); y = (f(x+h) - f(x))/h endfunction function y=fpp(x,h); y = (fp(x+h,h) - fp(x))/h endfunction kod = 0 wi=0 // zad if f(a) * f(b) < 0 then wi= 1 x(wi) = a while ~(fp(a,h)*fp(b,h) > 0 && fpp(a,h) * fpp(b,h) > 0) if ~(wi<n_max) then kod = 1 break; end wi = wi + 1; x(wi) = (a+b)/2; if abs(x(wi) - x(wi-1)) < 10^(-r) then kod = 2; break; end; if f(a) * f(x(wi)) < 0 then b = x(wi); else a = x(wi); end end if kod == 0 then // metoda r-f. wi = wi + 1; if fp(a,h) * fpp(a,h) < 0 then c = a x(wi) = b else c = b x(wi) = a end while(wi < n_max) wi = wi + 1 x(wi) = x(wi-1) - f(x(wi-1)) * (c-x(wi-1))/(f(c) - f(x(wi-1))) if abs(x(wi) - x(wi-1)) < 10^(-r) then kod = 2; break; end end end else kod = 3 end
Editor is loading...
Leave a Comment