coin-change
unknown
python
2 years ago
322 B
1
Indexable
import math, functools coins = [1,2,5] amount = 11 @functools.cache def M(i, n): if n == 0: return 0 if n < 0: return math.inf if i < 0: return math.inf take_coin = 1 + M(i, n-coins[i]) skip_coin = M(i-1, n) return min(take_coin, skip_coin) print(M(len(coins)-1, amount))
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