Advent of Code 2023-11
radulle
javascript
2 years ago
1.3 kB
89
Indexable
function solve(input) {
return [process(...parse(input), 2), process(...parse(input), 1000000)];
}
function parse(input) {
const galaxies = [];
const rows = [];
const cols = [];
input = input.split("\n").map((e) => e.split(""));
for (let i = 0; i < input.length; i++) {
if (!input[i].includes("#")) rows.push(i);
for (let j = 0; j < input[i].length; j++)
if (input[i][j] === "#") galaxies.push([i, j]);
}
for (let j = 0; j < input[0].length; j++)
if (!input.map((e) => e[j]).includes("#")) cols.push(j);
return [galaxies, rows, cols];
}
function process(galaxies, rows, cols, expand) {
expand -= 1;
const dist = [];
for (let i = 0; i < galaxies.length; i++) {
dist[i] = [];
for (let j = i; j < galaxies.length; j++) {
dist[i][j] =
Math.abs(galaxies[i][0] - galaxies[j][0]) +
Math.abs(galaxies[i][1] - galaxies[j][1]) +
expand *
cols.filter(
(e) =>
e > Math.min(galaxies[i][1], galaxies[j][1]) &&
e < Math.max(galaxies[i][1], galaxies[j][1])
).length +
expand *
rows.filter((e) => e > galaxies[i][0] && e < galaxies[j][0]).length;
}
}
return dist
.map((e) => e.reduce((acc, cur) => acc + cur, 0))
.reduce((acc, cur) => acc + cur, 0);
}
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